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 Write an equation of the line that is perpendicular to 2x + 4y = 6 and passes through the point (6,4).

 

 

A)y = 2x + 4

B)y = 2x - 8

C)y = -2x + 16

D)y = - 1/2x + 4

E)y = -1/2x + 7

kikidylm  Nov 29, 2018

Best Answer 

 #1
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\(2x+4y=6\\ y = -\dfrac 1 2 x + \dfrac 3 2\\ m=-\dfrac 1 2 \\ m_\perp=-\dfrac{1}{m} = 2\\ \text{so using point slope form the equation defining the perpendicular line is}\\ (y-4)=2(x-6) \\ -2x+y = -8\)

Rom  Nov 29, 2018
 #1
avatar+3198 
+1
Best Answer

\(2x+4y=6\\ y = -\dfrac 1 2 x + \dfrac 3 2\\ m=-\dfrac 1 2 \\ m_\perp=-\dfrac{1}{m} = 2\\ \text{so using point slope form the equation defining the perpendicular line is}\\ (y-4)=2(x-6) \\ -2x+y = -8\)

Rom  Nov 29, 2018

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