Write an equation of the line that is perpendicular to 2x + 4y = 6 and passes through the point (6,4).
A)y = 2x + 4
B)y = 2x - 8
C)y = -2x + 16
D)y = - 1/2x + 4
E)y = -1/2x + 7
2x+4y=6y=−12x+32m=−12m⊥=−1m=2so using point slope form the equation defining the perpendicular line is(y−4)=2(x−6)−2x+y=−8
+511 
