Flying against the wind, an airplane travels 3850 km in 7 hours. Flying with the wind, the same plane travels 4350 km in 5 hours. What is the rate of the plane in still air and what is the rate of the wind?
+128474 Flying against the wind, an airplane travels 3850 km in 7 hours. Flying with the wind, the same plane travels 4350 km in 5 hours. What is the rate of the plane in still air and what is the rate of the wind?
Let P be the plane's rate in still air
Let the rate of the wind = W
So we have that Time * Rate = Distance
So
7(P - W) = 3850 divide both sides by 7
5(P + W) = 4350 divide both sides by 5
P - W = 550
P + W = 870 add these
2P = 1420 divide both sides by 2
P = 710 (kph)
And
710 - W = 550
W = 710 - 550
W = 160 [kph]
That's a STRONG WIND !!!!
+2094 LOL!!!!!!! Anyway, here's another way to do it.
x=Plane's rate in still air
y= Rate of the wind
x-y=550
x+y=870
Then, use the elimination method. (subtract)
-2y=-320
y=160km/h
Then, we know that the plane's rate in still air is 550+160, which is 710 km/h.
It is DEFINITELY A STRONG WIND!!!!!!!
