I'm going to assume that there is an original equation of y=(-1/2)x+b with a y-value of 2 and an x-value of -3, solve for b.
\(2=-\frac{1}{2}(-3)+b\)
Multiply.
\(2=\frac{3}{2}+b\)
Subtract b from both sides.
\(\frac{4}{2}-\frac{3}{2}=b\)
\(b=\frac{1}{2}\)
Now plug back into original equation.
\(y=-\frac{1}{2}x+\frac{1}{2}\)
In a problem with mx+b format, m is the slope, or in this problem \(m=-\frac{1}{2}\).