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find the slope 2=-1/2(-3)+b

owlface13  Nov 15, 2017
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I'm going to assume that there is an original equation of y=(-1/2)x+b with a y-value of 2 and an x-value of -3, solve for b.

$$2=-\frac{1}{2}(-3)+b$$

Multiply.

$$2=\frac{3}{2}+b$$

Subtract b from both sides.

$$\frac{4}{2}-\frac{3}{2}=b$$

$$b=\frac{1}{2}$$

Now plug back into original equation.

$$y=-\frac{1}{2}x+\frac{1}{2}$$

In a problem with mx+b format, m is the slope, or in this problem $$m=-\frac{1}{2}$$.