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In triangle ABC, CA=4sqrt(2), CB=4sqrt(3), and A=60 degrees. What is B in degrees?

 May 22, 2021
 #1
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By the Cosine Law, B = 75 degrees.

 May 22, 2021
 #3
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You should use the Law of sines (or trig) to solve this problem.

 

∠A = 60º        a = 4√3        b = 4√2         ∠B = ?

 

a / sinA = b / sinB

 

sinB = (sinA * b) / a

 

∠B = 45º

Guest May 22, 2021
 #2
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Angle B = 45º

 

Angle C = 75º

 May 22, 2021

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