In triangle ABC, CA=4sqrt(2), CB=4sqrt(3), and A=60 degrees. What is B in degrees?
By the Cosine Law, B = 75 degrees.
You should use the Law of sines (or trig) to solve this problem.
∠A = 60º a = 4√3 b = 4√2 ∠B = ?
a / sinA = b / sinB
sinB = (sinA * b) / a
∠B = 45º
Angle B = 45º
Angle C = 75º