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Sorry, I might be reposting this, but on my screen, my question kept glitching so this is why I'm posting this question again.

 

In a survey of 200 people, 161 reported owning a car, 58 owned a bicycle and 74 had a valid mass transit pass. A total of 12% of the survey respondents reported owning all three, while 2.5% reported owning none. How many of the people surveyed owned exactly one of the three?

 

I would only like some help leading towards the answer, as I want to understand how to do it.

 Jan 5, 2021
 #1
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200*2.5=5

5 people have none 

200*12=24

24 people have both 

Hope this helps😀

 Jan 5, 2021
 #2
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Ok, so I found out that the answer is 121, but could you help a bit more explaining it please?

Guest Jan 5, 2021
 #3
avatar+536 
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What i would do is try to find make a [triple] venn diagram

you know 2.5% dont have any, so we only count 195 people. 

The 12% would go in the middle section.

 Jan 5, 2021
 #4
avatar+303 
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Ok so you know that their is 200 people and and their is three iteams.

Then you know that 12% of the people who took the servey have all the iteam and 2.5% have none of the iteam so you need to find how many people have all and none of the iteams then you subterct the sum of any people have all and none of the iteams form the 200 people you will know how many people have one of the three iteams.

 

Hope this help😄

 Jan 5, 2021
edited by hihihi  Jan 5, 2021
 #5
avatar+536 
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theres also should be people with two of the transportations

i dont think the problem would be that easy

MooMooooMooM  Jan 5, 2021
 #6
avatar+303 
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I forgot about that dang

 Jan 6, 2021
 #7
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One hundred twenty one.

 Jan 6, 2021
 #8
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There are 195 people who have SOMETHING.

 

161+58+74= 293      So there is (293-195) = 98 overlap (double or triple counting)

 

people that have car and bike =a 

                            Car and pass = b

                             Pass and Bike =c      (Draw a 3 circle Venn Diagram to visualize)

 

a b and c are double counted    and    24  is triple counted

    So    a+b+c   + 2*24 = 98

         Then   a+b+c =50

Car only +24 +a   +b        + bike only +24 +a+c       + pass only + 24 + b + c   = 293

car only + bike only + pass only    + 2 (a+b+c)  + 3*24 =293

car only + bike only+ pass only = 293 - 2(50)-3(24)= 121

Guest Jan 6, 2021

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