(2x^3-3x^2+2x-4)
(x-3)
Polynomial long division is the way to go here, katie-leigh
2x^2 + 3x + 11
x - 3 [2x^3 - 3x^2 + 2x - 4]
2x^3 - 6x^2
----------------------------------------
3x^2 + 2x
3x^2 - 9x
--------------------
11x - 4
11x - 33
--------------
29
So the answer is 2x^2 + 3x + 11 remainder 29 / [ x- 3]