For the numbers $n=0$ through $n=4,$ compute the remainder when $n^5-n$ is divided by 5. What is the sum of these five remainders?
[0^5 - 0] / 5 = 0/5 = R 0
[1^5 - 1 ] / 5 = 0/5 = R 0
[2^5 - 2] / 5 = 30/ 5 = R 0
[ 3^5 - 3 ] / 5 = 240/5 = R 0
[ 4^5 - 4 ] /5 = 1020 / 5 = R0
Sum = 0