An object dropped from a height of 600 feet has a height, h(t), in feet after t seconds have elapsed, such that h(t)=600-16t^2. Express t as a function of height h, and find the time to reach a height of 50 feet.
h-600 = -16t^2
sqrt [(600-h)/16) = t Taking only the positive square root ...for a positive time value
sqrt(600-h)/4 = t Put in 50 for h
sqrt(550)/4 = t = 5.86 seconds