+0  
 
0
1375
1
avatar+98 

An object dropped from a height of 600 feet has a height, h(t), in feet after t seconds have elapsed, such that h(t)=600-16t^2. Express t as a function of height  h, and find the time to reach a height of 50 feet.

 Apr 7, 2020
 #1
avatar+37146 
+1

h=600-16t^2.

h-600 = -16t^2

 

sqrt  [(600-h)/16)  = t      Taking only the positive square root ...for a positive time value 

 

sqrt(600-h)/4 = t        Put in 50 for h

 

sqrt(550)/4 = t     = 5.86 seconds

 Apr 7, 2020

0 Online Users