+1072 Find the positive constant k so that the equation 
has a unique solution in x.
+934 When plugging in values of x that are squares, you get k to equal 2.
So your answer should be k= 2.
Hope it helps!
+248 First square the equation and rearrange
3sqrt(x)=x+k
9x=x2+2kx+k2
0=x2+2kx-9x+k2
Factor to make it a quadratic
0=x2+(2k-9)x+k2
For a quadratic equation to have one solitution, the discrmimnant must be 0.
b2-4ac=0
Substitute in the coefficents:
(2k-9)2-4(1)(k2)=0
Expand
4k2-36k+81-4k2=0
Simplify
-36k+81=0
Solve
-4k+9=0
-4k=-9
k=2.25
