If x is a real number and \(x^2-7x+6<0\), what are the possible values for x? Use interval notation to express your answer.

Guest Apr 19, 2020

#1**+2 **

Hi guest!

First, let's solve this quadratic. When we solve it, we get an answer of x=1 and x=6.

So, we know the answer can be either:

\(x<1\),

\(1 or

\(x>6\)

Now we can just test values in the intervals to see if they satisfy the equation or not.

The only interval that satisfies the inequality is: \(1 . In interval notation, the answer is \(\boxed{x \in (1,6)}\)

I hope this helped you, guest!

:)

lokiisnotdead Apr 19, 2020