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If x is a real number and \(x^2-7x+6<0\), what are the possible values for x? Use interval notation to express your answer.

 Apr 19, 2020
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Hi guest!

 

First, let's solve this quadratic. When we solve it, we get an answer of x=1 and x=6.

So, we know the answer can be either:

 

 \(x<1\),

\(1  or

\(x>6\)

 

Now we can just test values in the intervals to see if they satisfy the equation or not. 

The only interval that satisfies the inequality is: \(1 . In interval notation, the answer is  \(\boxed{x \in (1,6)}\)

 

I hope this helped you, guest!

:)

 Apr 19, 2020

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