If x is a real number and \(x^2-7x+6<0\), what are the possible values for x? Use interval notation to express your answer.
+738 Hi guest!
First, let's solve this quadratic. When we solve it, we get an answer of x=1 and x=6.
So, we know the answer can be either:
\(x<1\),
\(1 or
\(x>6\)
Now we can just test values in the intervals to see if they satisfy the equation or not.
The only interval that satisfies the inequality is: \(1 . In interval notation, the answer is \(\boxed{x \in (1,6)}\)
I hope this helped you, guest!
:)
