+0  
 
0
60
1
avatar+80 

Suppose tan(θ) = − √ 3 and 0 ≤ θ ≤ π. What is the value of cos(θ)?

 Dec 3, 2020
 #1
avatar+114592 
+1

tan (A)   =  y/x  =    -√3/1 = √3/-1  ..........since     A is between   0 and  pi.....then  x must be  a  2nd quadrant angle  since the tangent is  negative there

 

So.....the  cos (A)   will be also  be negative  in this quadrant

 

r =  sqrt  [ (-1)  + (√3)^2  ]  =  sqrt 4   =   2

 

cos (A)  =  x / r  =  - 1/2

 

 

cool cool cool

 Dec 3, 2020

46 Online Users

avatar
avatar
avatar