Triangle ABC is an isosceles right triangle with the measure of angle A equal to 90 degrees. The length of segment AC is 6 cm. What is the area of triangle ABC, in square centimeters?
If we have an isosceles right triangle....the legs will be of equal length
AC is one leg and AB is the other
And they both equal 6cm
And they form the base and height of the triangle
And the area of a right triangle =
[ Base * Height} / 2 = [ Product of the leg lengths ] / 2 =
[6 * 6 ] / 2 =
36 / 2 =
18 cm^2