Suppose that $h(x)=f^{-1}(x)$. If $h(2)=10$, $h(10)=1$ and $h(1)=2$, what is $f(f(10))$?
\(h(x)=f^{-1}(x)\)
\(h(2)=10 \)
\(h(1)=2 \)
\(f(f(10) \) ???
The points (2,10) and ( 1,2) are on the graph of h(x)
Since h(x) is the same as f-1(x) ...then the points (10,2) and (2, 1) are on the graph of f(x)
So f(10) = 2
And
f(f(10) = f(2) = 1
