The quadratic $x^2-3x+9=x+41$ has two solutions. What is the positive difference between these solutions?
x^2-3x+9 = x+41 subtract the right side from both sides
x^2 - 4x - 32 = 0 factor
(x - 8) (x + 4) = 0
Setting each factor to 0 and solving for x, we have that
x= 8 and x = -4
And the positive difference between these is
8 - (-4) =
12
+1452 
