Given that (a+3)^2 + (b-7)^2 + (c-a)^2 = 0, what is a+b+c?
Every part of the equation has to equal 0..
a = -3
b = 7
Then (c+3)^2 = 0, so c = -3
a+b+c = 1.
+1252 +1252 
