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Given that (a+3)^2 + (b-7)^2 + (c-a)^2 = 0, what is a+b+c? 

 Dec 24, 2019

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 #1
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Every part of the equation has to equal 0..

a = -3

b = 7

Then (c+3)^2 = 0, so c = -3

a+b+c = 1.

 Dec 24, 2019
 #1
avatar+1078 
0
Best Answer

Every part of the equation has to equal 0..

a = -3

b = 7

Then (c+3)^2 = 0, so c = -3

a+b+c = 1.

CoolStuffYT Dec 24, 2019

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