In an equation of the form with k = ax^2 + bx + c, the least possible value of k occurs at x = -b/(2a). In the equation k = (6x + 12)(x - 8) , what is the least possible value for k?
(6x + 12) ( x - 8) =
6x^2 + 12x - 48x - 96
6x^2 - 36x - 96
The min value occurs at x = -b / (2a) = 36 / ( 2 * 6) = 36 / 12 = 3
So k = 6(3)^2 -36(3) - 96 = 54 - 108 - 96 = -150
+20 
