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In an equation of the form with k = ax^2 + bx + c, the least possible value of k occurs at x = -b/(2a). In the equation k = (6x + 12)(x - 8) , what is the least possible value for k?

 Mar 23, 2021
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(6x + 12) ( x - 8)  =  

 

6x^2 + 12x - 48x  - 96

 

6x^2  - 36x  - 96

 

The  min  value  occurs at   x =  -b / (2a)  =  36  / ( 2 * 6)  =  36 / 12  =  3

 

So  k  =   6(3)^2  -36(3)  - 96  =   54 - 108 - 96  =  -150  

 

 

 

cool cool cool

 Mar 23, 2021

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