Line L1 represents the graph of 3x+4y = -14. Line L2 passes through the point -5,7 and is perpendicular to line L1. If line L2 represents the graph of y=mx+b, then find m+b.
Isolate y in 3x + 4y = -14 ==> y = 3x/4 - 14/4
Slope of Perpendicular = -4/3, point-slope form of equation y - 7 = -4/3(x + 5)
==> 3y - 21 = -4(x + 5) = -4x + 20
==> 3y = -4x + 41
==> y = -4/3*x + 41/3
m + b = -4/3 + 41/3 = 37/3
