+0

-1
46
2

The solution to the inequality $$\frac{x + c}{x^2 + ax + b} \le 0$$ is $$x \in (-\infty,-1) \cup [1,2).$$  Find $$a + b + c.$$

aHHH I'm so stuckkkk

Mar 30, 2020

#1
0

a + b + c = (-3) + 4 + (-2) = -1.

Mar 31, 2020
#2
0

it's wrong for some reason....i have another attempt...help please!

Guest Apr 1, 2020