The solution to the inequality \(\frac{x + c}{x^2 + ax + b} \le 0 \) is \(x \in (-\infty,-1) \cup [1,2).\) Find \(a + b + c. \)
aHHH I'm so stuckkkk
a + b + c = (-3) + 4 + (-2) = -1.
it's wrong for some reason....i have another attempt...help please!
