+0  
 
+1
50
12
avatar+74 

\(\sum_{i=2}^{∞} \frac{1}{i^3-i}\)

 

yeah that above (Hopefully you can see)
 

So I know that i^3 - i is factored as i(i+1)(i-1) and just fiddled around trying to find sensible patterns 

 

(Is it 1/4? I got that after like some random nonsense lol) 

 

Thanks

 

(Also can this just be answered (or not) but NOT end in a thread of people attacking eachother like my previous question? :] )

 Nov 8, 2022
edited by AutumnStorm  Nov 8, 2022
 #11
avatar+33270 
+1

As follows:

 

The third line above should have "Let j = i+1".

 Nov 8, 2022
edited by Alan  Nov 9, 2022
edited by Alan  Nov 9, 2022
 #12
avatar+74 
+1

Thanks, Alan!

AutumnStorm  Nov 8, 2022

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