Calculate \(a^{9} + b^{6} + c^4\div d^3\) assuming that \(a=0, b=1, c=2^3\) and \(d =2\).
You literally have this
(0)^9 + (1)^6 + [ (2^3)^4 ÷ (2)^3 ]
0 + 1 + [ 2^12 ÷ 2^3 ] =
1 + 2^9 =
513
However.... you may have meant
[ (0)^9 + (1)^6 + (2^3)^4 ] ÷ (2)^3 =
[ 1 + 2^12] / 2^3 =
[4097 ] / 8
