+65 The two quadrilaterals below have the same area. What is the height of the orange trapezoid?
+129852 Area of quadrilateral = 6 * 5 = 30
Area of trapezoid = (1/2) h * ( sum of base lengths )
30 = (1/2) h ( 3 + 7)
30 = (1/2) h (10)
30 = 5h divide both sides by 5
6 = h
The purple figure is a para\(\)llelogram, with an area of 5*6=30, since base*height=area...
The next figure is a trapezoid...and it's area is \(\frac{1}{2}{10}{h}=30\), and 5h=30, h=6.
-From Sneaky, maybe CPhill can guess who I am...
+220 To figure this out, we need to figure out the area of the pink parellelogram.
Evaluate 6*5 to get 30 square (units).
*The area of a trapezoid is ((a+b)/2)*h.
* = When I say a and b, those are the 3 and 7 side lengths.
Now, we can say the area is 5*h, or 5h.
Because the area of the parallelogram is 30 and the area is the same for both shapes, 5h must equal 30.
Therefore, h or height is 6.
~~Hypotenuisance
