We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.

+0

# help please

0
62
5
+55

The two quadrilaterals below have the same area. What is the height of the orange trapezoid?

Apr 19, 2019

### 5+0 Answers

#1
+100483
+1

Area of quadrilateral  =  6 * 5  = 30

Area of trapezoid  =  (1/2) h  * ( sum of base lengths )

30 = (1/2) h ( 3 + 7)

30  = (1/2) h (10)

30  =  5h    divide both sides by  5

6  =  h

Apr 19, 2019
#2
+1

The purple figure is a parallelogram, with an area of 5*6=30, since base*height=area...

The next figure is a trapezoid...and it's area is  $$\frac{1}{2}{10}{h}=30$$, and 5h=30, h=6.

-From Sneaky, maybe CPhill can guess who I am...

Apr 19, 2019
#3
+129
+1

To figure this out, we need to figure out the area of the pink parellelogram.

Evaluate 6*5 to get 30 square (units).

*The area of a trapezoid is ((a+b)/2)*h.

* =  When I say a and b, those are the 3 and 7 side lengths.

Now, we can say the area is 5*h, or 5h.

Because the area of the parallelogram is 30 and the area is the same for both shapes, 5h must equal 30.

Therefore, h or height is 6.

~~Hypotenuisance

Apr 20, 2019
#4
+55
+2

thanks, everyone!

Apr 20, 2019
#5
+129
-2

You're welcome, Donkey!!!

~~Hypotenuisance

Hypotenuisance  Apr 21, 2019