+0

0
218
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The two quadrilaterals below have the same area. What is the height of the orange trapezoid?

Apr 19, 2019

#1
+106539
+1

Area of quadrilateral  =  6 * 5  = 30

Area of trapezoid  =  (1/2) h  * ( sum of base lengths )

30 = (1/2) h ( 3 + 7)

30  = (1/2) h (10)

30  =  5h    divide both sides by  5

6  =  h

Apr 19, 2019
#2
+1

The purple figure is a parallelogram, with an area of 5*6=30, since base*height=area...

The next figure is a trapezoid...and it's area is  $$\frac{1}{2}{10}{h}=30$$, and 5h=30, h=6.

-From Sneaky, maybe CPhill can guess who I am...

Apr 19, 2019
#3
+128
0

To figure this out, we need to figure out the area of the pink parellelogram.

Evaluate 6*5 to get 30 square (units).

*The area of a trapezoid is ((a+b)/2)*h.

* =  When I say a and b, those are the 3 and 7 side lengths.

Now, we can say the area is 5*h, or 5h.

Because the area of the parallelogram is 30 and the area is the same for both shapes, 5h must equal 30.

Therefore, h or height is 6.

~~Hypotenuisance

Apr 20, 2019
#4
+64
+2

thanks, everyone!

Apr 20, 2019
#5
+128
-2

You're welcome, Donkey!!!

~~Hypotenuisance

Hypotenuisance  Apr 21, 2019