limx→0 (sin5x)/2x
and
limx→0 (tanx)/(xsecx)
i wanted to check if my answers and work were all right ! (5/2 and 1) thank youuuu:))))))
sin (5x) / 2x multiply top/bottom by 5
5sin (5x) / [ 5 * 2x]
(5/ 2) sin (5x) / [ 5x]
As x ⇒ 0 the limit of sin (5x) / [5x} = limit of sin (0) / 0 = 1
So....5/2 is correct !!!!
tan x sinx / cosx sin x * cos x sin x
_____ = ____________ = ___________ = _____
xsecx x [ 1 / cos x] x * cos x x
And the limit of the last function as x ⇒ 0 = 1 !!!!
Correct on both counts !!!