Line l(1) represents the graph of 3x + 4y = -14. Line 1(2) passes through the point (-5, 7), and is perpendicular to line l(1). If line l(2) represents the graph of y = mx + b, then find m + b.
Isolate y in 3x + 4y = -14 ==> y = 3x/4 - 14/4
Slope of Perpendicular = -4/3, point-slope form of equation y - 7 = -4/3(x + 5)
==> 3y - 21 = -4(x + 5) = -4x + 20
==> 3y = -4x + 41
==> y = -4/3*x + 41/3
m + b = -4/3 + 41/3 = 37/3
