+0

0
218
4

https://i.gyazo.com/86224be9e2479f2276a24a4bdf193cc0.png

Feb 27, 2018

#1
+99736
+2

I know a few

First one

The elevator is on the ground floor at  A

The max upward velocity occurs at   B

Second one

C - 5 seconds

D - acceleration.....change in velocity / change in time  =

[ 18 m/s - 0 m/s ]  / 5sec =    (18/5)m/s^2 =  (3.6)m/s^2

E - Don't know this one

F -  5 seconds

G -  acceleration  -

[ 0 m/s - 18m/s ] / [14s - 18s ]  =

-18m/s / [ -4sec] =  (-18/4)m/s^2  = -4.5m/s^2

H - don't know this one

I - don't know

Feb 27, 2018
#2
+18138
0

E. Goes from 18 m/s to 0 m/s in 4 seconds

Acceleration =  change in velocity / change in time

=  (0-18) / 4 = -4.5 m/s^2

H.  SImilar to E above   goes from  -18 m/s to 0/m/s in 5 seconds

0 -(-18) / 5 =  3.6 m/s^2

Feb 27, 2018
#3
+18138
+1

I)

The area UNDER a velocity graph is the distance travelled....We need only look at the first triangle

1/2  b x h

1/2 x 9 s x 18 m/s= 81 meters high = 10th floor

Feb 27, 2018
edited by Guest  Feb 27, 2018
#4
+99736
0

Thanks, EP  !!!!

CPhill  Feb 27, 2018