https://i.gyazo.com/86224be9e2479f2276a24a4bdf193cc0.png

https://i.gyazo.com/e163feb8a68d6a6e57748154ade6f874.png

questions on both links

Guest Feb 27, 2018

#1**+2 **

I know a few

First one

The elevator is on the ground floor at A

The max upward velocity occurs at B

Second one

C - 5 seconds

D - acceleration.....change in velocity / change in time =

[ 18 m/s - 0 m/s ] / 5sec = (18/5)m/s^2 = (3.6)m/s^2

E - Don't know this one

F - 5 seconds

G - acceleration -

[ 0 m/s - 18m/s ] / [14s - 18s ] =

-18m/s / [ -4sec] = (-18/4)m/s^2 = -4.5m/s^2

H - don't know this one

I - don't know

CPhill Feb 27, 2018

#2**0 **

E. Goes from 18 m/s to 0 m/s in 4 seconds

Acceleration = change in velocity / change in time

= (0-18) / 4 = -4.5 m/s^2

H. SImilar to E above goes from -18 m/s to 0/m/s in 5 seconds

0 -(-18) / 5 = 3.6 m/s^2

ElectricPavlov Feb 27, 2018

#3**+1 **

I)

The area UNDER a velocity graph is the distance travelled....We need only look at the first triangle

1/2 b x h

1/2 x 9 s x 18 m/s= 81 meters high = 10th floor

ElectricPavlov Feb 27, 2018

edited by
Guest
Feb 27, 2018