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Ellen works for a high-speed rail company that wants to develop a new rail line. Ellen’s project is to find a train that is the second fastest in the world. The Shinkansen Bullet Train in Japan is reported to go as fast as 320 kilometers per hour. The TGV train in France can reach speeds of 89.44 meters per second. Explain to Ellen how to find what speed her new train must go to be the second fastest in this group. Then, find an appropriate speed for Ellen’s train in miles per hour and use the formula distance = speed • time to find how far the train can go in 2.5 hours. Use complete sentences and show your work.

 Jul 12, 2014

Best Answer 

 #1
avatar+130515 
+5

First, let's calculate the speed of the TGV train.

Since there are 3600 seconds in an hour and it travels 89.44 meters/second, it must travel

3600*89.44m = 321,984 meters per hour. We need to divide this by 1000 to get the speed in km = 321.984 km/hr. Note that this is slightly faster than the Japanese train. So, if for instance, our train traveled 321km/hr, it would be the second fastest.

To convert this to mph, note that there are about 1.61 km in a mile. So....

321km/hr * 1 mile / 1.61 ≈ 199mph.

To find out the distance it can travel in 2.5 hrs., we have

Rate * Time = Distance

199mph * 2.5 hrs. = 497.5 miles

 

 Jul 13, 2014
 #1
avatar+130515 
+5
Best Answer

First, let's calculate the speed of the TGV train.

Since there are 3600 seconds in an hour and it travels 89.44 meters/second, it must travel

3600*89.44m = 321,984 meters per hour. We need to divide this by 1000 to get the speed in km = 321.984 km/hr. Note that this is slightly faster than the Japanese train. So, if for instance, our train traveled 321km/hr, it would be the second fastest.

To convert this to mph, note that there are about 1.61 km in a mile. So....

321km/hr * 1 mile / 1.61 ≈ 199mph.

To find out the distance it can travel in 2.5 hrs., we have

Rate * Time = Distance

199mph * 2.5 hrs. = 497.5 miles

 

CPhill Jul 13, 2014
 #2
avatar+118723 
0

sevenUP already answered this question here

http://web2.0calc.com/questions/can-you-please-help-anyone#r33

I can understand that all the "kiddie" posts made this one very hard to find but it has been sitting there for hours.

 Jul 13, 2014

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