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Let $0 \le a, b, c \le 5$ be integers. For how many ordered triples $(a,b,c)$ is $a^2b+b^2c+c^2a-ab^2-bc^2-ca^2 = 0$?

 

TYSM :D

 Mar 24, 2021
 #1
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There are 80 such triples.

 Mar 24, 2021
 #2
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Are you sure?

 

Please tell explanation.

CoolKid  Mar 24, 2021

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