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Let f(x)=23xx+5. Evaluate f(1)+f(2)+f(3)++f(999)+f(1000). This sum has 1000 terms, one for the result when we input each integer from 1 to 1000 into f.

 Apr 16, 2020
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Every term is -2, so the sum is -2000.

 Apr 16, 2020

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