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Let line 1 be the graph of 5x+8y=-9. Line 2 is perpendicular to line 1 and passes through the point (10,-10). If line 2 is the graph of the equation y=mx+b, then find m+b.

 Jul 8, 2021
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5x+8y=-9

8y=-5x-9

y=-5/8 x - 9/8

Perpendicular line's slope is -1/(-5/8) = 8/5

y=8/5x+b

Substitute (10, -10)

-10=8/5*10+b

b=-26

So 8/5+(-26) = -24.4=-122/5

 

You are very welcome!
:P

 Jul 8, 2021

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