When the expression 3x^2-24x+55 written in the form a(x+d)^2+e, where a, d, and e are constants, then what is the sum a+d+e?
3x^2 -24x + 55 complete the square
3 (x^2 - 8x + 55/3)
3(x^2 - 8x + 16 + 55/3 - 16)
3 [ (x -4)^2 + 55/3 - 48/3 ]
3[ (x - 4 )^2 + 7/3)
3(x - 4)^2 + 7
So
a = 3
d = -4
e = 7
And their sum = 6
