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When the expression 3x^2-24x+55 written in the form a(x+d)^2+e, where a, d, and e are constants, then what is the sum a+d+e?

Guest Dec 22, 2017
 #1
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3x^2 -24x + 55       complete the square

 

3 (x^2 - 8x   +  55/3)

 

3(x^2  - 8x  +  16  +  55/3  - 16)

 

3 [  (x -4)^2   + 55/3  - 48/3 ]

 

3[ (x - 4 )^2  +  7/3)

 

3(x - 4)^2  +  7

 

So

 

a =  3

d  = -4

e  = 7

 

And their sum  =  6

 

 

cool cool cool

CPhill  Dec 22, 2017

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