9^(x-1) over 3^(y+2) = 81 express y in terms of x
The equation 9^(x - 1)/3^(y + 2) = 81 can be rearranged to give 3^(y + 2) = 9^(x - 1). Taking the log of both sides, we have y + 2 = (x - 1)log(9). Therefore,
y = (x - 1)log(9) - 2
= 2(x - 1) - 2
= 2x - 2 - 2
= 2x - 4.
Thanks a lot.
I have another question
q1. ∫(3x4-4)/ (2x3) dx
