Let a, b, and c be constants, and suppose that the inequality (x-a)(x-b)/(x-c) <= 0 is true if and only if either x<-4 or |x-25|<=-1. Given that a
You can set a = 21, b = 26, c = 4, so a + 2b + 3c = 77.
no that is wrong the answer is 64
