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Let a, b,  and c be constants, and suppose that the inequality (x-a)(x-b)/(x-c) <= 0 is true if and only if either x<-4 or |x-25|<=-1. Given that a

 Oct 24, 2021
 #1
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You can set a = 21, b = 26, c = 4, so a + 2b + 3c = 77.

 Oct 24, 2021
 #2
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no that is wrong the answer is 64

 Oct 25, 2021

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