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The numbers 1, -1 and a+1 are the roots of the equation x^3+6x^2-2bx-3c-12=0. Find the values of a,b, and c.

 

TY :)

 Feb 26, 2021
 #1
avatar+34376 
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Put -1 in the equation

 

-1 + 6 + 2b- 3c -12 = 0

2b-3c = 7

 

Put 1 in the equation

1 + 6 - 2b-3c -12 = 0

-2b-3c = 5                                   Now you can solve for a and b   (hint: add the two red equations)

 

 

See if you can find   'a'     Hint     (x-a-1)   divided into the equation should leave no remainder....

 Feb 26, 2021

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