Find the sum of all solutions to the equation.
$4x(x-3) = 23$
4x(x - 3) = 23 ---> 4x2 - 12x = 23 ---> 4x2 - 12x - 23 = 0
Using the quadratic formula: x = [ 12 +/- sqrt( (-12)2 - 4(4)(-23) ) ] / [ (2)(4) ]
Write the two answers in reduced radical form and add them together ...
