+0

Halp ASAP!

+1
75
3
+21

five points $a$, $b$, $c$, $d$, and $o$ lie on a flat field. $a$ is directly north of $o$, $b$ is directly west of $o$, $c$ is directly south of $o$, and $d$ is directly east of $o$. the distance between $c$ and $d$ is 140 m. a hot-air balloon is positioned in the air at $h$ directly above $o$. the balloon is held in place by four ropes $ha$, $hb$, $hc$, and $hd$. rope $hc$ has length 150 m and rope $hd$ has length 130 m. how high is the balloon above the field (that is, the length of $oh$)?

Apr 18, 2023
edited by itsdshen112  Apr 18, 2023

#1
+1

Let c = oc, d = od, and h = oh.

Since HC = 150, then h^2 + c^2 = 150^2 by the Pythagorean Theorem. Since HD=130, then h^2+d^2=130%2. Since CD=140, then c^2+d^2=140^2. Adding the first two equations, we obtain 2h^2+c^2+d^2=150^2+130^2.
Since c^2+d^2=140^2, then

\begin{align*} 2h^2 + 140^2 &= 150^2 + 130^2 \\  2h^2 &= 150^2 + 130^2 - 140^2 \\ 2h^2 &= 2800 \\ h^2 &= 1400 \\ h &= \sqrt{1400} = \boxed{30\sqrt{11}}. \end{align*}

Therefore, OH = 30*sqrt(11).

Apr 18, 2023
#2
+1

Wait, OH = sqrt(1400) = 14*sqrt(10).

Guest Apr 18, 2023
#3
+21
0

First guy was right, but equations were wrong

itsdshen112  Apr 18, 2023