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In a rectangular coordinate system, the line 3y=x intersects the line 2x + 5y = 11 at point A. What is the sum of the coordinates of point A?

 

 

A triangular region is bounded by the two coordinate axes and the line given by the equation 2x+y=6. What is the area of the region, in square units?

 Apr 10, 2019
edited by Guest  Apr 10, 2019
 #1
avatar+111430 
+1

x = 3y

2x + 5y  = 11          sub the first equation into the second  for x

 

2(3y) + 5y = 11

6y + 5y = 11

11y = 11

y = 1

 

An d  x  = 3(1)  = 3

 

So  A  = (3, 1)   .....sum of coordinates  =  4

 

 

cool cool cool

 Apr 10, 2019
 #2
avatar+111430 
+1

Second one....the idea here is to find the x and y intercepts  of the line

 

x intercept....let y = 0

2x + 0 = 6

2x = 6

x = 3

 

y intercept......let x = 0

2(0) + y = 6

y = 6

 

 

Triangle area  =    (x int) (y int) /2    =     (3) (6) / 2   =   9  units^2

 

 

cool cool cool

 Apr 10, 2019

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