Janet spent 2/7 of her money on 4 pencils and 8 books. She then spent the remaining amount of money on 6 pencils, 10 toys and 12 books. How many toys could she buy with 6/7 of her money?
Janet spent 2/7 of her money on 4 pencils and 8 books. She then spent the remaining amount of money on 6 pencils, 10 toys and 12 books. How many toys could she buy with 6/7 of her money?
Let the price of 1 pencil ==P
Let the price of 1 book==B
Let the price of 1 toy==T
4P + 8B ==2/7,
6P + 12B ==5/7 - 10T, solve for T
T ==1/35
1/35T ==6/7
T==30 - number of toys she could buy with 6/7 of her money.
