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The roots of $7x^2 + x - 5 = 0$ are a and b. Compute $(a - 4)(b - 4).$

PLS HELP

 Mar 11, 2021
 #1
avatar+31281 
+1

Using the Quadratic Formula    with a = 7    b = 1     c = -5  

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

roots are   x=0.776739            x=−0.919596          

 

( .776739 -4)(-.919596 - 4 ) = .....................

 Mar 11, 2021
 #2
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No, you're supposed to use the vietas formula

Guest Mar 11, 2021
 #3
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Then THAT should be in your question post !

ElectricPavlov  Mar 11, 2021
 #4
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(a-4)(b-4) =

ab  -4a - 4 b + 16

-5/7   - 4 (-1/7)   + 16

-5/7 + 4/7 + 16 = -1/7 + 16    = 15 6/7

 Mar 11, 2021
 #5
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HOLY UR INSANe! First person to finally solve after 3 tries! noice man!

Guest Mar 11, 2021
 #6
avatar+31281 
+1

Welllll....you're welcome !    cheeky

 Mar 11, 2021

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