+0  
 
0
120
3
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Find \(n\) if \(n\cdot n! + n! = 720\), where \(n! = n\cdot (n-1)\cdot (n-2)\cdots 2\cdot 1\).

 Mar 19, 2023
 #2
avatar+38 
+1

5, the equation just becomes (n+1)n!=720 just looking at this the answer is 5.  5!=120

 Mar 20, 2023

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