In the diagram below, \( \overline{AD}\parallel\overline{BE}\) and A is not on \(\overline{BC}\). Line segments \(\overline{AD}\) and \(\overline{BC}\) intersect at P. Can \(\angle CAD=\angle CBE\)? Explain.
If AD is parallel to BE....then angles ADC and BEC are equal
But angle ACD is greater than angle BCE
So.. in triangles CAD and CBE.......this means that angle CAD is less than angle CBE