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In the diagram below, \( \overline{AD}\parallel\overline{BE}\) and A is not on \(\overline{BC}\). Line segments \(\overline{AD}\) and \(\overline{BC}\) intersect at P. Can \(\angle CAD=\angle CBE\)? Explain.

 Mar 6, 2020
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If AD  is parallel  to  BE....then  angles   ADC  and BEC  are equal

 

But  angle   ACD  is  greater than angle  BCE

 

So.. in triangles  CAD  and CBE.......this means that  angle  CAD  is less than angle  CBE

 

 

cool cool cool 

 Mar 6, 2020

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