Help plssss

We have a circle of raduis 8 and a triangle inside it. The area of the entire circle is pi*8^2=64pi. The answer is either A,C or E. It's probably A if the circle is drawn to scale because the shaded area and the non-shaded area are about the same size, and 64pi is \(\approx\) 201. A is \(\approx\) 83, which is the closest out of A,C and E to half of the circle.

We have an equilateral  triangle...

The area of this triangle  is  3(1/2) * 8^2  * sin (120°) =  3 (32) * √3 / 2  =  3 * 16 * √3  =

48√3  cm^ 2     (1)

The area of the circle  = pi * 8^2  =  64 pi   cm^2     (2)

So...the shaded area  is  (2)  - (1)  =  [ 64 pi  - 48√3 ] cm^2   =   "A"