In right triangle $ABC$, shown below, $\cos{B}=\frac{6}{10}$. What is $\tan{C}$?
C
4 5
A 3 B
cos B = 6/10 = 3/5 → sin C = 3/5
sin B = 8/10 = 4/5 → cos C = 4/5
tan C = sin C / cos C = (3/5) / (4/5) = 3 / 4
