f(x) = x/2 + 1 g(x) = 3x + 2
a) f(1) + g(2) =
1/2 + 1 + 3 (2) + 2 =
9 + 1/2 = 19 / 2
b ) We can solve this
3x + 2 = 11
3x = 9
x = 3 = g-1 (11)
In other words (3,11) is on g(x) so (11 , 3) is on g-1 (x)
c) We already know g-1(11)
So we can solve this
x/2 + 1 = 3
x/2 = 2
x = 4 = f-1(3)
So g-1(11) - f-1(3) = 3 - 4 = -1