If g ( 2x - 5 ) = 3x + 9 for all real x, then what is g ( 1 )?
g(1) = 3*1 + 9 = 12.
I think g(1) is actually g(2*1-5)
=^._.^=
I think you would have to set x as 3, since 2*3-5 = 1.
So 3*6+9 = 27