Graph the solution set of y < (x − 2)^2 + 1.
i just need to solution set I think i can figure out how to graph it
+32 First, we can graph the parabola by graphing $y=(x-2)^2+1.$ The vertex of the parabola is $(2,1)$ and the $y$-intercept is where $x=0$. This turns out to be $y=(-2)^2+1 = 5$, so the $y$-intercept is $(0,5)$. Therefore, we can use this information to graph the parabola. We find the solution set of this by setting a test point, $(0,0).$ If this test point satisfies the inequality, then the region in which the test point is included is the solution set. I'll let you take it from here.
