+0  
 
0
153
1
avatar

Graph the solution set of y < (x − 2)^2 + 1.

 

i just need to solution set I think i can figure out how to graph it

 Feb 26, 2021
 #1
avatar+32 
0

First, we can graph the parabola by graphing $y=(x-2)^2+1.$ The vertex of the parabola is $(2,1)$ and the $y$-intercept is where $x=0$. This turns out to be $y=(-2)^2+1 = 5$, so the $y$-intercept is $(0,5)$. Therefore, we can use this information to graph the parabola. We find the solution set of this by setting a test point, $(0,0).$ If this test point satisfies the inequality, then the region in which the test point is included is the solution set. I'll let you take it from here. 

 Feb 26, 2021
edited by BigBurger  Feb 26, 2021

38 Online Users

avatar
avatar
avatar
avatar
avatar