Graph the solution set of y < (x − 2)^2 + 1.

i just need to solution set I think i can figure out how to graph it

Guest Feb 26, 2021

#1**0 **

First, we can graph the parabola by graphing $y=(x-2)^2+1.$ The vertex of the parabola is $(2,1)$ and the $y$-intercept is where $x=0$. This turns out to be $y=(-2)^2+1 = 5$, so the $y$-intercept is $(0,5)$. Therefore, we can use this information to graph the parabola. We find the solution set of this by setting a test point, $(0,0).$ If this test point satisfies the inequality, then the region in which the test point is included is the solution set. I'll let you take it from here.

BigBurger Feb 26, 2021