Find the value of a so that the system has no solutions.
\(\begin{align*} y &= 11x+14 \\ 2y-4 &= ax \end{align*}\)
THIS IS CONFUSING ME I NEED HELP!!!
THANK YOU!!!
If the two lines are separate and parallel there will be no solutions. Rewrite 2y - 4 = ax as y = (a/2)*x + 2
This is parallel to y = 11x + 14 if a/2 = 11 (so that the slopes are the same); i.e. if a = 22.
THX A LOT! MEANS A LOT TO ME