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Find the value of a so that the system has no solutions.

\(\begin{align*} y &= 11x+14 \\ 2y-4 &= ax \end{align*}\)

 

THIS IS CONFUSING ME I NEED HELP!!!

THANK YOU!!!

 Mar 19, 2020
 #1
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If the two lines are separate and parallel there will be no solutions.  Rewrite 2y - 4 = ax as  y = (a/2)*x + 2

 

This is parallel to y = 11x + 14 if a/2 = 11 (so that the slopes are the same); i.e. if a = 22.

 Mar 19, 2020
 #2
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THX A LOT! MEANS A LOT TO ME

 Mar 19, 2020

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