Help plz. Not sure.

There is only one value of y that satisfies the equation:

y ==3

[3/3+1 ==(3+3)/3] 

  2      ==     2

Hi Guest, 

So...

$\frac{y}{3}+1=\frac{\left(y+3\right)}{y}$

$y^2+3y=3\left(y+3\right)$

$y=3,\:y=-3$

The number of values of y: $2$