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The parabola y=ax^2+bx+c is graphed below. Find a+b+C. (The grid lines are one unit apart.)

 Mar 20, 2021
 #1
avatar+121000 
+1

The vertex  is  (2,1)

 

And  we have  the form

 

y = a(x - h)^2  +  k             where  ( h, k)  is  the vertex

 

And  the point  (0, 5)  is  on the graph....so...

 

5 = a (  0 - 2)^2 + 1

 

5 - 1  =  4a

 

4 = 4a

 

a = 1

 

So  we have

 

y= 1( x - 2)^2  + 1

 

y = x^2  -  4x  +  4 + 1

 

y = x^2  - 4x  +  5

 

a = 1  b  =  -4   c  = 5

 

a + b + c  =    1  - 4  + 5  =    2

 

 

cool cool cool

 Mar 20, 2021
edited by CPhill  Mar 20, 2021
 #2
avatar+203 
+1

Its 2 then right? Because 1-4=-3 and -3+5=2.

 Mar 20, 2021
edited by TheEarlyMathster  Mar 20, 2021
 #3
avatar+121000 
0

No prob .....

 

 

cool cool cool

CPhill  Mar 20, 2021
 #4
avatar+121000 
0

Oops small mistake...corrected  !!!

 

cool cool cool

CPhill  Mar 20, 2021

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