In rectangle WXYZ, A is on side WX such that AX = 4, B is on side YZ such that BY = 18, and C is on side XY such that ACB= 90 degrees and CY = 2CX. Find AB.
By the Pythagorean Theorem, AB = 4*sqrt(11).
AB cannot be shorter than BY!!!
ΔBCY and ΔACX are similar. Let CX be an N (CY = 2N)
N / 4 = 18 / 2N
N * 2N = 18 * 4
2N2 = 72
N = 6
XY = 3 * N = 18
AB = sqrt [ (XY)2 + (BY - AX)2 ]