Write an equation in slope-intercept form of the line that passes through (7, 2)(7, 2) and (2, 12)(2, 12).
two points (7,2), (2,12)the slope of a line segment joining them is given bym=2−127−2=−105=−2use point slope form with the first point(y−2)=−2(x−7)y=−2x+16
(7,2) and (2,12)
Find the slope = m = [ 12 -2] / [ 2 - 7 ] = 10 / -5 = -2
Using either point we have - I'll use (7, 2) - we have
y = m (x - 7) + 2
y = -2(x - 7) + 2 simplify
y = -2x + 14 + 2
y = -2x + 16
+48 
