Find all values of z such that {3-z}/{z+1} ≥ 1. Answer in interval notation.
+1252 \(\frac{3-z}{z+1} \geq 1, 3-z \geq z+1\)
Now we can add z and subtract 1 to both sides, then solve and get the interval notation. Can you solve that?
You are very welcome!
:P
